Suppose, the line lies on the plane . Then is equal to _______....

Given equation of line x - 2 = y - 2 - 5 = z + 2 2 ...... (i) and plane Line (i) passes through which lies on plane (ii). 2 + 6 + 4 + = 0 = - 12 Also, given line is perpendicular to normal of the plane (1) - 5(3) + 2(-2) = 0 = 19 + = 19...

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Suppose the line x 2 alpha y 2 5 z 2 2 lies on the plane x 3: null (Mathematics) | DivineJEE

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Mathematics

Exam

Mathematics

Suppose, the line

{{x - 2} \over \alpha } = {{y - 2} \over { - 5}} = {{z + 2} \over 2}

lies on the plane

x + 3y - 2z + \beta = 0

. Then

(\alpha + \beta )

is equal to _______.

Select an option to instantly check whether it is correct or wrong.

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