The given A.P. is 3,8,13, …, 373 Tn=a+(n−1) d ⇒ 373=3+(n−1) 5 ⇒ n=75 Sn=275[3+373]=14100 Numbers which are divisible by 3 are 3,18, …, 363. Tn′=3+(n′−1) 15 ⇒ 363=3+15 n′−15 ⇒ 15 n′=375 ⇒ n′=25 Sn′=225[3+363]=4575 ∴ { Required sum }=14100−4575=9525