The sum of the first n terms of the series (1^{2} + 2.2^{2} + 3^{2} + 2.4^{2} + 5^{2} + 2 . 6^{2} + ..) is (\frac{n(n + 1)^{2}}{2}, when n is even. when n is odd, the sum is: Sequence & Series (Mathematics) | DivineJEE
Exam
Mathematics
The sum of the first n terms of the series\\\n 12+2⋅22+32+2⋅42+52+2⋅62+………\n is 2n(n+1)2, when n is even. when n is odd,\n the sum is
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