The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad / s. The frequency of this simple harmonic oscillator is\_\_\_ Hz. [. take .pi=(22 / 7)]

boldsymbolomega=176 rad / sec f_ k=(omega / 2 pi)=(176 / 2 x 22) x 7 =(176 / 44) x 7 =4 x 7=28 Hz So frequency of oscillator =frac f_ k2=14 Hz

The kinetic energy of a simple harmonic oscillator is | null (Physics) | DivineJEE

JEE Mains 2026 21st January Shift 2

Physics

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of

176 \mathrm{rad} / \mathrm{s}

. The frequency of this simple harmonic oscillator is\_\_\_ Hz.

\left[\right.

take

\left.\pi=\frac{22}{7}\right]

176

Correct Answer:

\boldsymbol{\omega}=176 \mathrm{rad} / \mathrm{sec}\\

\mathrm{f}_{\mathrm{k}}=\frac{\omega}{2 \pi}=\frac{176}{2 \times 22} \times 7\\

=\frac{176}{44} \times 7\\

=4 \times 7=28 \mathrm{~Hz}\\

So frequency of oscillator

\\=\frac{\mathrm{f}_{\mathrm{k}}}{2}=14 \mathrm{~Hz}

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