A moving coil galvanometer has 100 turns and each turn has an area of 2.0 cm^2. The magnetic field produced by the magnet is 0.01 T and the deflection in the coil is 0.05 radian when a current of 10 mA is passed through it. The torsional constant of the suspension wire is x x 10^-5 N- m / rad. The value of x is _______ .

tau= BINAsin phi \ C theta= BINAsin 90^° \ C=frac BINAtheta=frac0.01 x 10 x 10^-3 x 100 x 2 x 10^-40.05 \ =4 x 10^-5 N- m / rad . \ x=4\

A moving coil galvanometer has 100 turns and each turn ... | null (Physics) | DivineJEE

Exam

Physics

A moving coil galvanometer has 100 turns and each turn has an area of

2.0 \mathrm{~cm}^2

. The magnetic field produced by the magnet is

0.01 \mathrm{~T}

and the deflection in the coil is 0.05 radian when a current of

10 \mathrm{~mA}

is passed through it. The torsional constant of the suspension wire is

x \times 10^{-5} \mathrm{~N}-\mathrm{m} / \mathrm{rad}

. The value of

x

is _______ .

Correct Answer:

\begin{aligned} & \tau=\text { BINAsin } \phi \\\\ & \mathrm{C} \theta=\text { BINAsin } 90^{\circ} \\\\ & \mathrm{C}=\frac{\mathrm{BINA}}{\theta}=\frac{0.01 \times 10 \times 10^{-3} \times 100 \times 2 \times 10^{-4}}{0.05} \\\\ & =4 \times 10^{-5} \mathrm{~N}-\mathrm{m} / \mathrm{rad} . \\\\ & \mathrm{x}=4\end{aligned}

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