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The distance of the point P3 4 4 from the point of inte... | null (Mathematics) | DivineJEE

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Mathematics

Exam

Mathematics

The distance of the point P(3, 4, 4) from the point of intersection of the line joining the points. Q(3,

-

4,

-

5) and R(2,

-

3, 1) and the plane 2x + y + z = 7, is equal to ______________.

Correct Answer:

7

Explanation

\overrightarrow {QR} : - {{x - 3} \over 1} = {{y + 4} \over { - 1}} = {{z + 5} \over { - 6}} = r

\Rightarrow (x,y,z) \equiv (r + 3, - r - 4, - 6r - 5)

Now, satisfying it in the given plane.

We get

r = -2

so, required point of intersection is T(

1, -2, 7

).

Hence, PT = 7.

Select an option to instantly check whether it is correct or wrong.

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