The common difference of the A.P. is 2 more than the common difference of A.P. . If and , then is equal to...

aligned& a_1, a_2, , a_n (C D=d) \\& b_1, b_2, , b_m (C D=d+2) \\& a_40=a+39 d=-159 \\& a_100=a+99 d=-399 (1)aligned : equation (1)aligned& a+39(-4)=-159 \\& a=156-159=-3 \\& a_70=a+69 d=-3+69(-4)=-279=b_100 \\& b_100=-279 \\& b_1+99(d+2)=-279 \\& b_1-198=-279 b_1=-81aligned...

The common difference of the A.P. b_{1},b_{2},.,b_{m} is 2 more than the common difference of A.P. a_{1},a_{2},,a_{n}. If a_{40} = - 159,a_{100} = - 399 and b_{100} = a_{70}, then b_{1} is equal to: Sequence & Series (Mathematics)

The common difference of the A.P.

b_{1},b_{2},\ldots.,b_{m}

is 2\n more than the common difference of A.P.

a_{1},a_{2},\ldots,a_{n}

.\n If

a_{40} = - 159,a_{100} = - 399

and

b_{100} = a_{70}

, then\n

b_{1}

is equal to

If a_1, a_2, a_n are in A.P. where a_i>0 for all i show that &\frac{1}{\sqrt{a_1}+\sqrt{a_2}}+\frac{1}{\sqrt{a_2}+\sqrt{a_3}}+\cdots+\frac{1}{\sqrt{a_{n-1}}+\sqrt{a_n}}&=\frac{n-1}{\sqrt{a_1}+\sqrt{a_n}}

For any odd integer n ? 1,n^{3} - (n - 1)^{3} + + ( - 1)^{n - 1}1^{3} =

Different A.P. are constructed with the first term 100 , the last term 199, and integral common differences. The sum of the common differences of all such A.P. having at least 3 terms and at most 33 terms is

If a_{n} = \frac{3}{4} - ( \frac{3}{4} )^{2} + ( \frac{3}{4} )^{3} + ( - 1)^{n - 1}( \frac{3}{4} )^{n} and b_{n} = 1 - a_{n}, then find the least natural number n_{0} such that b_{n} > a_{n}\forall n ? n_{0}

Let A_{1},G_{1} and H_{1} denote the arithmetic, geometric and harmonic means . respectively of two distinct positive numbers. For n ? 2 let A_{n - 1} and H_{n - 1} have . arithmetic, geometric and harmonic means as A_{n},G_{n},H_{n} respectively. Which of the following statements is correct?

If a_{1},a_{2},a_{3}, are in A.P. such that a_{1} + a_{7} + a_{16} = 40, then the sum of the first 15 terms of this A.P. is

The sum of the first n terms of the series (1^{2} + 2.2^{2} + 3^{2} + 2.4^{2} + 5^{2} + 2 . 6^{2} + ..) is (\frac{n(n + 1)^{2}}{2}, when n is even. when n is odd, the sum is

Number of 4 -digit numbers that are less than or equal to 2800 and either divisible by 3 or by 11 , is equal to

Let a,b be two non-zero real numbers. If p and r are the roots of the equation x^{2} - 8ax + 2a = 0 and q and s are the roots of the equation \end{enumerate} x^{2} + 12bx + 6b = 0, such that \frac{1}{p},\frac{1}{q},\frac{1}{r},\frac{1}{s} are in A.P., then a^{- 1} - b^{- 1} is equal to

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