On complete combustion, 0.492 g of an organic compound gave 0.792 g of CO_2. The % of carbon in the organic compound is ___________ (Nearest integer)

Weight of C in 0.792 gm CO_2 =(12 / 44) x 0.792=0.216 \ \% of C in compound =(0.216 / 0.492) x 100 \ =43.90 \%

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On complete combustion 0492 g of an organic compound ga... | null (Chemistry) | DivineJEE

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Chemistry

Exam

Chemistry

On complete combustion, $0.492 \mathrm{~g}$ of an organic compound gave $0.792 \mathrm{~g}$ of $\mathrm{CO}_{2}$ . The % of carbon in the organic compound is ___________ (Nearest integer)

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Correct Answer:

Explanation

Weight of

\mathrm{C}

0.792 \mathrm{gm}

\mathrm{CO}_2

\begin{aligned} & =\frac{12}{44} \times 0.792=0.216 \\\\ & \% \text { of } C \text { in compound }=\frac{0.216}{0.492} \times 100 \\\\ & =43.90 \% \end{aligned}

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