Consider the cell at 25 CZn Zn2 aq 1M Fe3 aq Fe2 aq PtsThe f: (Chemistry) | DivineJEE
Exam
Chemistry
Consider the cell at 25∘C Zn | Zn2+ (aq), (1M) || Fe3+ (aq), Fe2+ (aq) | Pt(s) The fraction of total iron present as Fe3+ ion at the cell potential of 1.500 V is x × 10−2. The value of x is ______________. (Nearest integer) (Given : EFe3+/Fe2+0=0.77V, EZn2+/Zn0=−0.76V)