Number of integral terms in the expansion of \7^((1 / 2))+11^((1 / 6))\^824 is equal to _________.

General term in expansion of ((7)^1 / 2+(11)^1 / 6)^824 is t_ r+1= ^824 C_ r(7)^frac824- r2(11)^ r / 6 For integral term, r must be multiple of 6. Hence r=0,6,12, ....... 822

Number of integral terms in the expansion of 7frac 121... | null (Mathematics)

General term in expansion of

\left((7)^{1 / 2}+(11)^{1 / 6}\right)^{824}

\mathrm{t}_{\mathrm{r}+1}={ }^{824} \mathrm{C}_{\mathrm{r}}(7)^{\frac{824-\mathrm{r}}{2}}(11)^{\mathrm{r} / 6}

For integral term, $r$ must be multiple of 6.

Hence

r=0,6,12, ....... 822

Explanation

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