Let the mean and variance of 7 observations , be 8 and 16 respectively. Two numbers are chosen from one after another without replacement, then the probability, that the smaller number among the two c...

Mean (Given) Variance (Given) (sum is 14 product is 48 ) Since problem states and Now set Now we choose two numbers one after author without replacement total outcomes We want the prob. That the smaller number among the two is less than 4 smaller smaller $ =1-630=45 $...

Let the mean and variance of 7 observations 2 4 10 x 12 14 y: null (Mathematics)

Let the mean and variance of 7 observations

2,4,10, x, 12,14, y, x>y

, be 8 and 16 respectively. Two numbers are chosen from

\{1,2,3, \mathrm{x}-4, \mathrm{y}, 5\}

one after another without replacement, then the probability, that the smaller number among the two chosen numbers is less than 4 , is:

The area of the region enclosed by the parabolas y=4x-x^2 and 3y=(x-4)^2 is equal to

Ten different letters of an alphabet are given. Words with five letters are formed from these given letters. Then the number of words which have atleast one letter repeated, is

For (2 leq r leq n,binom{n}{r} + 2binom{n}{r - 1} + binom{n}{r - 2} =)

The minimum number of elements that must be added to the relation R = {(a,b),(b,c),(b,d)} on the set { a,b,c,d} so that it is an equivalence relation is

For integers n and r let n r nCr ifn ge r ge 0 0 otherwise

The integral int_0^1 \frac{1}{7^{\left[\frac{1}{x}\right]}} {dx}, where [.] denotes the greatest integer function is equal to

The area enclosed by the curves xy+4y=16 and x+y=6 is equal to :

Area of the region (x,y):x^2+(y-2)^2≤4,x^2≥2y is

Let A = { 1,3,4,6,9} and B = { 2,4,5,8,10}. Let R be a relation defined on A X B such that R = {( ( a_{1},b_{1} ), ( a_{2},b_{2} )):a_{1} ? b_{2} and b_{1} ? a_{2}}. Then the number of elements in the set R is

Let Z be the set of integers. If A = { x in Z:2^{(x + 2) ( x^{2} - 5x + 6 )} = 1 } and = { x in Z : - 3 < 2x - 1 < 9}, then the . number of subsets of the set A X B is

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