Let Q be the foot of the perpendicular from the point P7 2 1: (Mathematics) Question | DivineJEE | DivineJEE

Mathematics

Let Q be the foot of the perpendicular from the point P(7,

-

2, 13) on the plane containing the lines

{{x + 1} \over 6} = {{y - 1} \over 7} = {{z - 3} \over 8}

and

{{x - 1} \over 3} = {{y - 2} \over 5} = {{z - 3} \over 7}

. Then (PQ)², is equal to ___________.

Select an option to instantly check whether it is correct or wrong.

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