Let \(a_{1},a_{2},a_{3},\ldots\) be terms of an A.P. If \(\frac{a_{1} + a_{2} + \ldots + a_{p}}{a_{1} + a_{2} + \ldots + a_{q}} = \frac{p^{2}}{q^{2}},p \neq q\), then \(\frac{a_{6}}{a_{21}}\) equals