If the sum of first terms of an A.P. is , then the sum of squares of these terms is...

(c) : Let the A.P. be We have which holds for all implying and Then the A.P. is The sum of square of these terms &nbsp...

If the sum of first n terms of an A.P. is cn^{2}, then the sum of squares of these n terms is: Sequence & Series (Mathematics)

If the sum of first

n

terms of an A.P. is

cn^{2}

, then the sum of squares of these

n

terms is

\frac{n\left( 4n^{2} - 1 \right)c^{2}}{6}

\frac{n\left( 4n^{2} + 1 \right)c^{2}}{3}

\frac{n\left( 4n^{2} - 1 \right)c^{2}}{3}

\frac{n\left( 4n^{2} + 1 \right)c^{2}}{6}