Mathematics
If the sum of first \(n\) terms of an A.P. is \(cn^{2}\), then the sum
of squares of these \(n\) terms is
A
\(\frac{n\left( 4n^{2} - 1 \right)c^{2}}{6}\)
B
\(\frac{n\left( 4n^{2} + 1 \right)c^{2}}{3}\)
C
\(\frac{n\left( 4n^{2} - 1 \right)c^{2}}{3}\)
D
\(\frac{n\left( 4n^{2} + 1 \right)c^{2}}{6}\)
Select an option to instantly check whether it is correct or wrong.
