Mathematics
Let \(a_{1},a_{2},a_{3},\ldots\ldots\). be an A.P. If
\(\frac{a_{1} + a_{2} + \ldots + a_{10}}{a_{1} + a_{2} + \ldots + a_{p}} = \frac{100}{p^{2}}\),
\(p \neq 10\), then \(\frac{a_{11}}{a_{10}}\) is equal to
A
\(\frac{19}{21}\)
B
\(\frac{100}{121}\)
C
\(\frac{21}{19}\)
D
\(\frac{121}{100}\)
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