(c) : R{(a,b):3a − 3b + is an irrational number } Reflexive : For (a,a), we have 3a − 3a + = which is an irrational . number. ∴ R is reflexive Symmetric : Let (a,b) ∈ R i.e., 3a − 3b + is an irrational number Now, we need to check (b,a) ∈ R or not. Let 3a = and 3b = 8 then 3a − 3b+ = − 8 + = 2 − 8, which is an irrational . . number but 3b − 3a + = 8 − + = 8, which is not an irrational ∴ For (a,b) ∈ R,(b,a) ∈/ R ∴ R is not symmetric Transitive : Let (a,b) and (b,c) ∈ R Let 3a = 8,3b = 2,3c = then, 3a − 3b + = 8 − 2 + = 8 −, which is an irrational also, 3b − 3c + = 2 − + = 2, which is an irrational but 3a − 3c + = 8 − + = 8, which is not an irrational ⇒ (a,c) ∈/ R ∴ R is not transitive.