51.
(3): Let we have set
A={1,2,3}
\end{enumerate}
By definition, we can say that\\
For reflexivity ;
(1,1)(2,2) and
(3,3)∈R\\
For symmetry
;(2,1)(1,2)∈R\\
For transitivity
(1,2)∈R and
(2,3)∈R⇒(1,3)∈R
But according to the question, For not symmetric
;(2,1) and
(3,2)∈/R\\
So,
R1={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}\\
R2={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)(2,1)}
and
R3={(1,1),(2,2),(3,3),(1,2)(2,3)(1,3)(3,2)}
\begin{enumerate}
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