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In the line alpha x 4 y sqrt 7 where alpha in R touches the : null (Mathematics) | DivineJEE

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Mathematics

JEE Mains 2026 21st January Shift 2

Mathematics

In the line

\alpha x+4 y=\sqrt{7}

, where

\alpha \in R

, touches the ellipse

3 x^{2}+4 y^{2}=1

at the point

P

in the first quadrant, then one of the focal distances of P is :

A

\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{11}}

B

\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{5}}

C

\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{5}}

D

\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{7}}

Select an option to instantly check whether it is correct or wrong.

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