In the ground state of atomic FeZ 26 the spinonly magnetic m

Question

In the ground state of atomic Fe(Z = 26), the spin-only magnetic moment is ____________ x 10^(-1) BM. (Round off to the Nearest Integer). [Given : sqrt 3 = 1.73, sqrt 2 = 1.41 ]

DivineJEE · Accepted Answer

_26Fe = [Ar]3d^64s^2No. of unpaired electrons = 4mu = sqrt n(n + 2) BM = sqrt 4(4 + 2) = sqrt 24 = 2sqrt 3 x 2 = 2[1.73 x 1.41]= 4.8786 BM= 48.78 x 10^ - 1 BM

Explanation

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