If P is a point on the circle $\mathrm{x}^{2}+\mathrm{y}^{2}=4, \mathrm{Q}$ is a point on the straight line $5 \mathrm{x}+\mathrm{y}+2=0$ and $\mathrm{x}-\mathrm{y}+1=0$ is the perpendicular bisector of PQ , then 13 times the sum of abscissa of all such point P is $\_\_\_\_$ .