Mathematics
Given sum of the first \(n\) terms of an A.P. is \(2n + 3n^{2}\).
Another A.P. is formed with the same first term and double of the
common difference, the sum of \(n\) terms of the new A.P. is\
A
\(n + 4n^{2}\)
B
\(6n^{2} - n\)
C
\(n^{2} + 4n\)
D
\(3n + 2n^{2}\)
Select an option to instantly check whether it is correct or wrong.
