(a): Let terms of the A.P. are a−2 d, a−d, a, a+d, a+2 d. Given, sum of terms =25 ⇒ 5 a=25 ⇒ a=5 Also, product of terms = 2520[Given] ⇒(5−2 d)(5−d) 5(5+d)(5+2 d)=2520 ⇒(25−4 d2)(25−d2)=504 ⇒ 625−100 d2−25 d2+4 d4=504 ⇒ 4 d4−125 d2+121=0 ⇒ 4 d4−121 d2−4 d2+121=0 ⇒(d2−1)(4 d2−121)=0 ⇒ d= ± 1, d= ± 211 Since, d= ± 1 does not give 2−1 as one of the term of the A.P., so d= ± 211 ∴ The required A.P. is −6,−21, 5, 221, 16. Thus, greatest term is 16 .