Coagulating value of the electrolytes AlCl_3 and NaCl for As_2 S_3 are 0.09 and 50.04 respectively. The coagulating power of AlCl_3 is x times the coagulating power of NaCl. The value of x is ___________.

Coagulating value of the electrolytes AlCl3 and NaCl for As2: null (Chemistry)

The coagulating power of an electrolyte is inversely proportional to its coagulating value. That is,

\text{Coagulating power} = \frac{1}{\text{Coagulating value}}

Therefore, the coagulating power of AlCl₃ is

\frac{1}{0.09}

and the coagulating power of NaCl is

\frac{1}{50.04}

We are asked to find the factor by which the coagulating power of AlCl₃ is greater than the coagulating power of NaCl. This factor is given by the ratio

x = \frac{\text{Coagulating power of AlCl₃}}{\text{Coagulating power of NaCl}} = \frac{\frac{1}{0.09}}{\frac{1}{50.04}} = \frac{50.04}{0.09}

x = \frac{50.04}{0.09} \approx 556.22

So, the coagulating power of AlCl₃ is approximately 556 times the coagulating power of NaCl.

However, since the problem asks for the nearest integer, the answer would be 556.

Explanation

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