For , the least value of , for which are three consecutive terms of an A.P., is equal to :...

This simplifies to: Let . Since , we know . The expression becomes: Substituting : ...

For x ? 0, the least value of K, for which 4^{1 + x} + 4^{1 - x},\frac{K}{2},16^{x} + 16^{- x} are three consecutive terms of an A.P., is equal to :: Relations (Mathematics)

For

x \geq 0

, the least value of

K

, for which

4^{1 + x} +

4^{1 - x},\frac{K}{2},16^{x} + 16^{- x}

are three consecutive terms of an A.P., is equal to :