The r.m.s speed of oxygen molecules at 47^° C is equal to that of the hydrogen molecules kept at \_\_\_\_ ^° C. (Mass of oxygen molecule/mass of hydrogen molecule=32/2)

V_ rms=sqrtfrac3 RT M V_ rmsO_2= V_ rmsH_2 T_ O_2=273+47=320 K sqrtfrac3 RT_ O_2 M_ O_2=sqrtfrac3 RT_ H_2 M_ H_2 frac T_2 M_ O_2=frac T_ H_2 M_ H_2 (320 / 32)=frac T_ H_22 T_ H_2=20 K T_ H_2=-253^° C

The r m s speed of oxygen molecules at 47 circ C is equ... | null (Physics)

\mathrm{V}_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}}\\

\mathrm{V}_{\mathrm{rmsO}_{2}}=\mathrm{V}_{\mathrm{rmsH}_{2}}\\

\mathrm{T}_{\mathrm{O}_{2}}=273+47=320 \mathrm{~K}\\

\sqrt{\frac{3 \mathrm{RT}_{\mathrm{O}_{2}}}{\mathrm{M}_{\mathrm{O}_{2}}}}=\sqrt{\frac{3 \mathrm{RT}_{\mathrm{H}_{2}}}{\mathrm{M}_{\mathrm{H}_{2}}}}\\

\frac{\mathrm{T}_{2}}{\mathrm{M}_{\mathrm{O}_{2}}}=\frac{\mathrm{T}_{\mathrm{H}_{2}}}{\mathrm{M}_{\mathrm{H}_{2}}}\\

\frac{320}{32}=\frac{\mathrm{T}_{\mathrm{H}_{2}}}{2}\\

\mathrm{T}_{\mathrm{H}_{2}}=20 \mathrm{~K}\\

\mathrm{T}_{\mathrm{H}_{2}}=-253^{\circ} \mathrm{C}

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