The oxidation states of transition metal atoms in K2Cr2O7 KM

Question

The oxidation states of transition metal atoms in K_(2)Cr_(2)O_(7), KMnO_(4) and K_(2)FeO_(4), respectively, are x, y and z. The sum of x, y and z is _______.

DivineJEE · Accepted Answer

K_(2)Cr_(2)O_(7) Let oxidation state of Ce 2(+1) + 2x + 7(–2) = 0 => x = +6 In K_(2)Cr_(2)O_(7), Transition metal (Cr) present in +6 oxidation state. KMnO_(4) (+1) + y + 4(–2) = 0 => x = +7 In KMnO_(4), transition metal (Mn) present in +7 oxidation state. K_(2)FeO_(4) 2(+1) + z + 4(–2) = 0 => x = +6 In K_(2)FeO_(4), transition metal (Fe) present in +6 oxidation state. Therefore x + y + z = 6 + 7 + 6 = 19

Explanation

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