The ratio of ^14 C ^12 C in a piece of wood is 18 part that of atmosphere. If half life of ^14 C is 5730 years, the age of wood sample is ________ years.

t= ( ^14 C / ^12 C)_ atmosphere ( ^14 C / ^12 C)_ wood sample As per the question, ( ^14 C / ^12 C)_ wood ( ^14 C / ^12 C)_ atmosphere =18 So, t=&

The ratio of frac 14 C 12 C in a piece of wood is frac 18 pa: (Chemistry) | DivineJEE

Exam

Chemistry

The ratio of

\frac{{ }^{14} \mathrm{C}}{{ }^{12} \mathrm{C}}

in a piece of wood is

\frac{1}{8}

part that of atmosphere. If half life of

{ }^{14} \mathrm{C}

is 5730 years, the age of wood sample is ________ years.

$\lambda t=\ln \frac{\left({ }^{14} C /{ }^{12} C\right)_{\text {atmosphere }}}{\left({ }^{14} C /{ }^{12} C\right)_{\text {wood sample }}}$

As per the question,

$\frac{\left({ }^{14} C /{ }^{12} C\right)_{\text {wood }}}{\left({ }^{14} C /{ }^{12} C\right)_{\text {atmosphere }}}=\frac{1}{8}$

So, $\lambda t=\ln 8$

$\frac{\operatorname{In} 2}{t_{1 / 2}} t=\ln 8$

$t=3 \times t_{1 / 2}=17190 \text { years }$

Select an option to instantly check whether it is correct or wrong.

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