The number of N atoms in 681 g of C 7 H 5 N 3 O 6 is x 10 21 . The value of x is (N A = 6.02 10 23 mol -1 ) (Nearest Integer)

The number of N atoms in 681 g of C7H5N3O6 is x x 1021 The v: null (Chemistry)

Molar mass of

{C_7}{H_5}{N_3}{O_6}

= 12

\times

7 + 5 + 14

\times

3 + 16

\times

= 227 gm

Given mass of

{C_7}{H_5}{N_3}{O_6}

= 681 gm

\therefore

Moles of

{C_7}{H_5}{N_3}{O_6}

= {{681} \over {227}} = 3

In one molecule of

{C_7}{H_5}{N_3}{O_6}

, 3 N atoms present.

\therefore

In 1 mole

{C_7}{H_5}{N_3}{O_6}

, 3 moles of N atoms presents.

\therefore

In 3 moles of

{C_7}{H_5}{N_3}{O_6}

, 3

\times

3 = 9 moles of N atoms presents.

We know, 1 mole of N atoms = 6.02

\times

10²³ N atoms.

\therefore

9 moles of N atoms = 9

\times

6.02

\times

10²³ = 54.18

\times

10²³ = 5418

\times

10²¹