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The neutralization occurs when 10 mL of 0.1M acid 'A' is allowed to react with 30 mL of 0.05 M base M(OH)2. The basicity of the acid 'A' is __________.
[M is a metal]
Milieq of acid A=A=A= Milieq of base M(O H)2M(O H)_{2}M(O H)2
(M × V × n− Factor A=(M × V × n− Factor )M(OH)2 [n− Factor of M(OH)2=2] 0.1 × 10 × n −Factor = 0.05 × 30 × 2 (n− Factor )A =3 \begin{aligned} & \left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor }_{A}\right.=(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor })_{\mathrm{M}(\mathrm{OH})_{2}} \\ & \left[\mathrm{n}-\text { Factor of } \mathrm{M}(\mathrm{OH})_{2}=2\right] \\ &0.1 \times 10 \times \mathrm{n} \text {-Factor }= 0.05 \times 30 \times 2 \\ & (\mathrm{n}-\text { Factor })_{\mathrm{A}} =3 \end{aligned} (M × V × n− Factor A=(M × V × n− Factor )M(OH)2 [n− Factor of M(OH)2=2] 0.1 × 10 × n −Factor = 0.05 × 30 × 2 (n− Factor )A =3
Hence basicity of acid AAA is 3.
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