The moles of methane required to produce 81 g of water ... | null (Chemistry) | DivineJEE

Exam

Chemistry

The moles of methane required to produce 81 g of water after complete combustion is _____________ $\times$ 10^{$-$ 2} mol. [nearest integer]

Correct Answer:

225

\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}

POAC on

\mathrm{H}

atom

\begin{aligned} &\mathrm{n}_{\mathrm{CH} 4} \times 4=\mathrm{n}_{\mathrm{H} 2 \mathrm{O}} \times 2 \\\\ &\mathrm{n}_{\mathrm{CH}_4}=\frac{81}{18} \times 2 \times \frac{1}{4}=\frac{81}{36} \\\\ &\mathrm{n}_{\mathrm{CH}_4}=2.25 \\\\ &=225 \times 10^{-2} \end{aligned}

Nearest Integers

=225

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