The ionization energy of sodium in kJ mol^-1, if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is _______.

E=frac1240lambda( nm) eV \ =(1240 / 242) eV \ =5.12 eV \ =5.12 x 1.6 x 10^-19 \ =8.198 x 10^-19 J / atom \ =494 kJ / mol \

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The ionization energy of sodium in kJ mol1 if electroma... | (Chemistry) | DivineJEE

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Chemistry

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Chemistry

The ionization energy of sodium in $\mathrm{~kJ} \mathrm{~mol}^{-1}$ , if electromagnetic radiation of wavelength $242 \mathrm{~nm}$ is just sufficient to ionize sodium atom is _______.

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Explanation

$\begin{aligned} & \mathrm{E}=\frac{1240}{\lambda(\mathrm{nm})} \mathrm{eV} \\ & =\frac{1240}{242} \mathrm{eV} \\ & =5.12 \mathrm{eV} \\ & =5.12 \times 1.6 \times 10^{-19} \\ & =8.198 \times 10^{-19} \mathrm{~J} / \text { atom } \\ & =494 \mathrm{~kJ} / \mathrm{mol} \end{aligned}$