Surface tension of two liquids having same densities T ... | null (Physics)

JEE Mains 2026 21st January Shift 2

Physics

Surface tension of two liquids (having same densities),

\mathrm{T}_{1}

and

\mathrm{T}_{2}

, are measured using capillary rise method utilizing two tubes with inner radii of

r_{1}

and

r_{2}

where

r_{1}>r_{2}

. The measured liquid heights in these tubes are

\mathrm{h}_{1}

and

\mathrm{h}_{2}

respectively. [Ignore the weight of the liquid about the lowest point of miniscus]. The heights

\mathrm{h}_{1}

and

\mathrm{h}_{2}

and surface tensions

\mathrm{T}_{1}

and

\mathrm{T}_{2}

satisfy the relation :

h_{1} < h_{2}

and

T_{1} = T_{2}

\mathrm{h}_{1}=\mathrm{h}_{2}

and

\mathrm{T}_{1}=\mathrm{T}_{2}

\mathrm{h}_{1}>\mathrm{h}_{2}

and

\mathrm{T}_{1}=\mathrm{T}_{2}

h_{1} > h_{2}

and

T_{1} < T_{2}

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