Methylation of 10 g of benzene gave 92 g of toluene Cal... | null (Chemistry) | DivineJEE

Exam

Chemistry

Methylation of 10 g of benzene gave 9.2 g of toluene. Calculate the percentage yield of toluene __________. (Nearest integer)

Correct Answer:

{C_6}{H_6} + C{H_3}Cl\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{}} {C_6}{H_5}C{H_3} + HCl

10 gm of C₆H₆ =

{{10} \over {78}}

mole

Moles of methylbenzene should be obtained =

{{10} \over {78}}

mole

=

\left( {{{10} \over {78}} \times 92} \right)gm

\therefore

{{{A_y}} \over {{T_y}}} = \%

yield

= {{9.2} \over {920}} \times 78 \times 100 \Rightarrow 78\%

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