(a): We have,
A={(x,y)
∈Z×Z:(x−2)2+y2≤4},\\
B={(x,y)∈Z×Z:x2+y2≤4} and
C={(x,y)∈Z×Z:(x−2)2
+(y−2)2≤4}\\
Intersection of
A and
B is shown by graph as given.
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\includegraphics[width=3.11678in,height=2.13299in]{vertopal_a09d5a7ae2de483db956e76c708a9bbe/media/image4.jpg}
So,
A∩B={(0,0),(1,0),(2,0),
(1,1),(1,−1)}\\
∴ n(A∩B)=5 Also, intersection of
A and
C is
shown by graph as given.\\
So,
A∩C={(1,1),(2,0),(2,1),
(2,2),(3,1)}\\
⇒n(A∩C)=5 Number of relations from
(A∩B)
to
(A∩C)
\includegraphics[width=2.13129in,height=1.93121in]{vertopal_a09d5a7ae2de483db956e76c708a9bbe/media/image6.jpg}
=25×5=225=2p⇒p=25
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