The Rate of Reaction (ROR) for a reaction can be calculated based on the changes in concentrations of the reactants or the products over time. In the given reaction,
KClO3+6FeSO4+3H2SO4→KCl+3Fe2(SO4)3+3H2O
The rates of reaction can be written as :
ROR=−ΔtΔ[KClO3]=6−1ΔtΔ[FeSO4]=3+1ΔtΔ[Fe2(SO4)3]
From this, we can express the rate of formation of
Fe2(SO4)3 in terms of the change in concentration of
FeSO4 :
ΔtΔ[Fe2(SO4)3]=21Δt−Δ[FeSO4]
We know that the initial concentration of
FeSO4 was 10 M and after 30 minutes (or 1800 seconds), it became 8.8 M. Substituting these values in, we get :
=2130×60(10−8.8)=0.333×10−3
To express the rate in terms of
10−6molL−1s−1, we multiply the rate by
103 :
=333×10−6molL−1s−1
Therefore, the rate of production of
Fe2(SO4)3 is
333×10−6molL−1s−1.
