If the sum of the first $n$ terms of the series $\sqrt{3} + \sqrt{75} + \sqrt{243} + \sqrt{507} + \ldots$ is $435\sqrt{3}$, then $n$ equals - Math Practice Question | divineJEE

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If the sum of the first $n$ terms of the series $\sqrt{3} + \sqrt{75} + \sqrt{243} + \sqrt{507} + \ldots$ is $435\sqrt{3}$, then $n$ equals

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