If \(gcd(m,n) = 1\) and \(1^{2} - 2^{2} + 3^{2} - 4^{2} + \ldots. + (2021)^{2}\) \(- (2022)^{2} + (2023)^{2} = 1012m^{2}n\), then \(m^{2} - n^{2}\) is equal to - Math Practice Question | divineJEE