If 75 of a first order reaction was completed in 90 minutes

Question

If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes) _______. (Take : log 2 = 0.30; log 2.5 = 0.40)

DivineJEE · Accepted Answer

t_(75%) = 90 min = 2 × t_(1/2) => t_(1/2) = 45 min Rate constant, K = 0.693 / 45 min^(-1) Time for completion of 60% of the reaction, t_(60%) = 2.303 / Klog 10 / 4 = 2.303 x 45 / 0.693log 2.5 = 60 min

Explanation

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