For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _________ x 10^(-3) s^(-1). (Round off to the Nearest Integer). [Given : log_(10)2 = 0.301, ln10 = 2.303]

k = 1 / tln [ a / a - x ]k = 2.303 / 570log ( 100 / 32 )k = 2.303 / 570[ log (10^2) - log 2^5 ]k = 2.303 / 570 x 0.5k = 2 x 10^ - 3s^ - 1

For a certain first order reaction 32 of the reactant i... | null (Chemistry) | DivineJEE

Exam

Chemistry

For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _________

\times

10^{$-$ 3} s^{$-$ 1}. (Round off to the Nearest Integer). [Given : log₁₀2 = 0.301, ln10 = 2.303]

Correct Answer:

k = {1 \over t}\ln \left[ {{a \over {a - x}}} \right]

k = {{2.303} \over {570}}\log \left( {{{100} \over {32}}} \right)

k = {{2.303} \over {570}}\left[ {\log ({{10}^2}) - \log {2^5}} \right]

k = {{2.303} \over {570}} \times 0.5

k = 2 \times {10^{ - 3}}{s^{ - 1}}

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