Among the following species N_2, ~N_2^+, N_2^-, N_2^2-, O_2, O_2^+, O_2^-, O_2^2- the number of species showing diamagnesim is _______________.

Among the following species N2 N2 N2 N22 O2 O2 O2 O22 the: null (Chemistry)

Those species which have unpaired electrons are called paramagnetic species.

And those species which have no unpaired electrons are called diamagnetic species.

(1)

N_2

has 14 electrons.

Moleculer orbital configuration of

N_2

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,{\sigma _{2p_z^2}}

Here no unpaired electron present, so it is diamagnetic.

(2) Moleculer orbital configuration of

N_2^{ + }

(13 electrons)

=

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,{\sigma _{2p_z^1}}

Here in

N_2^{ + }

, 1 unpaired electron present, so it is paramagnetic.

(3)

\mathrm{N}_{2}^{2-}

has 16 electrons.

Moleculer orbital configuration of

\mathrm{N}_{2}^{2-}

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,\,{\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \,\,{\sigma _{2p_z^2}}\,\,{\pi _{2p_x^2}}\,= \,{\pi _{2p_y^2}}\,\pi _{2p_x^1}^ * = \,\,\pi _{2p_y^1}^ *

Here 2 unpaired electron present, so it is paramagnetic.

(4)

\mathrm{N}_{2}^{-}

has 15 electrons.

Moleculer orbital configuration of

\mathrm{N}_{2}^{-}

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,\,{\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \,\,{\sigma _{2p_z^2}}\,\,{\pi _{2p_x^2}}\,= \,{\pi _{2p_y^2}}\,\pi _{2p_x^1}^ * = \,\,\pi _{2p_y^0}^ *

Here 1 unpaired electron present, so it is paramagnetic.

(a)

O_2^{2−}

has 18 electrons.

Moleculer orbital configuration of

O_2^{2−}

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\sigma _{2p_z^2}}\,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,\pi _{2p_x^2}^ * \, = \,\pi _{2p_y^2}^ *

Here is no unpaired electron so it is diamagnetic.

(b)

O_2^{−}

has 17 electrons.

Moleculer orbital configuration of

O_2^{2−}

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\sigma _{2p_z^2}}\,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,\pi _{2p_x^2}^ * \, = \,\pi _{2p_y^1}^ *

Here 1 unpaired electron present, so it is paramagnetic.

(c)

O_2

has 16 electrons.

Moleculer orbital configuration of

O_2

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,\,{\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \,\,{\sigma _{2p_z^2}}\,\,{\pi _{2p_x^2}}\,= \,{\pi _{2p_y^2}}\,\pi _{2p_x^1}^ * = \,\,\pi _{2p_y^1}^ *

Here 2 unpaired electron present, so it is paramagnetic.

(d)

O_2^{+}

has 15 electrons.

Moleculer orbital configuration of

O_2^{+}

{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,\,{\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \,\,{\sigma _{2p_z^2}}\,\,{\pi _{2p_x^2}}\,= \,{\pi _{2p_y^2}}\,\pi _{2p_x^1}^ * = \,\,\pi _{2p_y^0}^ *

Here 1 unpaired electron present, so it is paramagnetic.

Explanation

The electronic configuration of Pt atomic number 78 is

Consider the following reaction approaching equilibrium at 2

What is the freezing point depression constant of a solvent

Consider the following elements In Tl Al Pb Sn and Ge The mo

The principle of column chromatography is

The amphoteric oxide among V2O3 V2O4 and V2O₅ upon reaction

The maximum prescribed concentration of copper in drinking w

If liquids A and B form an ideal solution

In the sixth period the orbitals that are filled are

Consider the cell at 25 CZn Zn2 aq 1M Fe3 aq Fe2 aq PtsThe f

Download Divine JEE App

Quick Links

Exam Categories

Contact Info

Divine JEE