At 10 minutes, the pressure increased by 2x:
800+2x=1600
The rate constant (k) can be found as:
k=102.303log400800=102.303×log2
For 30 minutes, we can set up the equation:
k=302.303log800−y800
102.303×log2=302.303log(800−y800)
Solving for y:
(800−y800)=8
800−y=100
Now we can find the total pressure after 30 minutes:
Total pressure = (800 - y) + 2y + y
Total pressure = 100 + 1400 + 700
Total pressure = 2200 mm Hg
So, the total pressure of the system after 30 minutes is 2200 mm Hg.
