AB2 is 10 dissociated in water to A2 and B The boiling point

Question

AB_(2) is 10% dissociated in water to A^(2+) and B^(-). The boiling point of a 10.0 molal aqueous solution of AB_(2) is __________^°C. (Round off to the Nearest Integer).[Given : Molal elevation constant of water K_(b) = 0.5 K kg mol^(-1) boiling point of pure water = 100^°C]

DivineJEE · Accepted Answer

AB_(2) leftrightharpoons A^(+) + 2B^(-) Therefore For AB_(2), n = 3i = 1 + (n - 1)alpha= 1 + (3 - 1) x 0.1= 1.2Now, DeltaT_(b) = K_(b) (im) => T_(b) - T_b^o = 1.2 x 0.5 x 10 => T_(b) - 100 = 6 => T_(b) = 106

Explanation

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