A mixture of hydrogen and oxygen contains 40 \% hydrogen by mass when the pressure is 2.2 bar. The partial pressure of hydrogen is bar. (Nearest Integer)

40 \% w / w hydrogen gas is given in mixture of H_2 and oxygen. Wt. of H_2=40 g Wt. of O_2=60 g chi_ H_2=frac n_ H_2 n_ H_2+ n_ O_2 =frac(40 / 2)(40 / 2)+(60 / 32) =(20 / 20+1.875) =(20 / 21.875)=0.914 P_ H_2=chi_ H_2 x P_ T =0.914 x 2.2 =2.01 = 2 bar

A mixture of hydrogen and oxygen contains 40 hydrogen b... | null (Chemistry)

40 \% \,\mathrm{w} / \mathrm{w}

hydrogen gas is given in mixture of

\mathrm{H}_{2}

and oxygen.

Wt. of

\mathrm{H}_{2}=40 \mathrm{~g}

Wt. of

\mathrm{O}_{2}=60 \mathrm{~g}

\chi_{\mathrm{H}_{2}}=\frac{\mathrm{n}_{\mathrm{H}_{2}}}{\mathrm{n}_{\mathrm{H}_{2}}+\mathrm{n}_{\mathrm{O}_{2}}}

=\frac{\frac{40}{2}}{\frac{40}{2}+\frac{60}{32}}

=\frac{20}{20+1.875}

=\frac{20}{21.875}=0.914

\mathrm{P}_{\mathrm{H}_{2}}=\chi_{\mathrm{H}_{2}} \times \mathrm{P}_{\mathrm{T}}

=0.914 \times 2.2

=2.01 \simeq 2 \mathrm{bar}

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