Dimension[x(t)]=[L]$\\$

${[\mathrm{A}]=[\mathrm{L}]} \\$

${[B]=[L]} \\$

${[C]=\left[\mathrm{LT}^{-2}\right]} \\$

${[\mathrm{D}]=[\mathrm{L}]} \\$

${\left[\frac{\mathrm{ABC}}{\mathrm{D}}\right]=\left[\frac{\mathrm{L} \times \mathrm{L} \times \mathrm{LT}^{-2}}{\mathrm{~L}}\right]=\left[\mathrm{L}^2 \mathrm{~T}^{-2}\right]}$