A hydrocarbon P C 4 H 8 on reaction with HCl gives an | null (Chemistry) | DivineJEE

JEE Mains 2026 21st January Shift 1

Chemistry

A hydrocarbon ' P '

\left(\mathrm{C}_{4} \mathrm{H}_{8}\right)

on reaction with HCl gives an optically active compound ' Q '

\left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{Cl}\right)

which on reaction with one mole of ammonia gives compound ' R '

\left(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\right)

. ' R ' on diazotization followed by hydrolysis gives ' S '. Identify

\mathrm{P}, \mathrm{Q}, \mathrm{R}

and S .

Select an option to instantly check whether it is correct or wrong.

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