A gas based geyser heats water flowing at the rate of 5.0 litres per minute from 27^°C to 87^°C. The rate of consumption of the gas is ____ g/s. (Take heat of combustion of gas = 5.0 × 104J/g) specific heat capacity of water = 4200 J/kg. °C

Water flow rate = 5 l/min = (5 / 60) kg/s Therefore Power of heater = (dm / dt)SDelta T = (1 / 12) x 4200 x 60 W Therefore Let the rate of consumption of gas be x g/s. Therefore x x 5.0 x 10^4 = (1 / 12) x 4200 x 60 => x = 4200 x 10^-4 = 0.42 g/s

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Physics

JEE Mains 2026 21st January Shift 1

Physics

A gas based geyser heats water flowing at the rate of

5.0

litres per minute from

27^\circ\text{C} \text{ to } 87^\circ\text{C}

. The rate of consumption of the gas is ____ g/s. (Take heat of combustion of gas =

5.0 × 104J/g

) specific heat capacity of water =

4200 J/kg. °C

2.1

4.2

0.42

0.21

Prev Next

Explanation

Water flow rate

= 5\text{ l/min} = \frac{5}{60}\text{ kg/s}

\therefore \text{Power of heater} = \frac{dm}{dt}S\Delta T = \frac{1}{12} \times 4200 \times 60\text{ W}

\therefore

Let the rate of consumption of gas be

x\text{ g/s}

\therefore x \times 5.0 \times 10^4 = \frac{1}{12} \times 4200 \times 60

\Rightarrow x = 4200 \times 10^{-4} = 0.42\text{ g/s}

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