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Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x×10−1x\times10^{-1}x×10−1. The value of xxx is ___________ (Nearest integer).
Assume complete dissociation.
pH=12, pH+pOH=14 pOH=14−12=2 [OH−]=10−2 mol L Ca(OH)25 × 10−3 ⟶ Ca2+5 × 10−3+2 OH−10−2 \begin{aligned} & \mathrm{pH}=12, \\ & \mathrm{pH}+\mathrm{pOH}=14 \\ & \mathrm{pOH}=14-12=2 \\ & {\left[\mathrm{OH}^{-}\right]=10^{-2} \mathrm{~mol} \mathrm{~L}} \\ & \underset{5 \times 10^{-3}}{\mathrm{Ca}(\mathrm{OH})_2} \longrightarrow \underset{5 \times 10^{-3}}{\mathrm{Ca}^{2+}}+\underset{10^{-2}}{2 \mathrm{OH}^{-}} \end{aligned} pH=12, pH+pOH=14 pOH=14−12=2 [OH−]=10−2 mol L 5 × 10−3Ca(OH)2 ⟶ 5 × 10−3Ca2++10−22 OH−
Moles of Ca(OH)2\mathrm{Ca}(\mathrm{OH})_2Ca(OH)2 in 1000 mL=5 × 10−31000 \mathrm{~mL}=5 \times 10^{-3}1000 mL=5 × 10−3
Millimoles in 100 mL=5 × 10−1100 \mathrm{~mL}=5 \times 10^{-1}100 mL=5 × 10−1
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