A collimated beam of light of diameter 2 mm is propagating along x-axis. The beam is required to be expanded in a collimated beam of diameter 14 mm using a system of two convex lenses. If first lens has focal length 40 mm, then the focal length of second lens is __________ mm.

(40 / 2) = (f / 14) => f = 280 mm Correct Answer : 280

A collimated beam of light of diameter 2 mm is propagat... | null (Physics) | DivineJEE

JEE Mains 2026 21st January Shift 1

Physics

A collimated beam of light of diameter

2\text{ mm}

is propagating along x-axis. The beam is required to be expanded in a collimated beam of diameter

14\text{ mm}

using a system of two convex lenses. If first lens has focal length

40\text{ mm}

, then the focal length of second lens is __________

\text{mm}

\frac{40}{2} = \frac{f}{14}

\Rightarrow f = 280\text{ mm}

Correct Answer : 280

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