If A = \sum_{n = 1}^{\infty}\mspace{2mu}\frac{1}{( 3 + ( - 1)^{n} )^{n}} and B = \sum_{n = 1}^{\infty}\mspace{2mu}\frac{( - 1)^{n}}{( 3 + ( - 1)^{n} )^{n}}, then \frac{A}{B} is equal to:: Sequence & Series (Mathematics) | DivineJEE