6∫0π∣2sin2xcosx+sin2x∣dx6∫0π4sinxcos2x+2sinxcosxdxI=12∫0πsinx2cos2x+cosx
Put cosx=t,−sinxdx=dtI=−12∫1−12t2+tdtI=12(∫−1−1/2(2t2+t)dt+∫−1/20−(2t2+t)dt+∫01(2t2+t)dt)I=17
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